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ATP Nice 2013 predictions
| ATP Nice 2013 predictions / Francúzsko, antuka , ATP Nice 2013 Tenis live kvalifikace |
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| May 20, 2013 14:00 |
čtvrtfinále | Silva Dutra Rogerio (Braz.) [2 BYE] (90) | 53.10% | 2 | 6 | 7 | I H2H O AI | ||||
| Jouan Romain (Fra.) (305) | 46.90% | 0 | 2 | 6 (6) | |||||||
| May 20, 2013 12:35 |
čtvrtfinále | Stakhovsky Sergiy (Ukr.) [4 BYE] (102) | 55.75% | 2 | 6 | 6 | 6 | I H2H O AI | |||
| Laaksonen Henri (Švaj.) (259) | 44.25% | 1 | 7 (6) | 2 | 4 | ||||||
| May 20, 2013 11:05 |
čtvrtfinále | Cecchinato Marco (Tal.) (358) | 33.33% | 2 | 6 | 7 | I H2H O AI | ||||
| De Bakker Thiemo (Hol.) [3 BYE] (92) | 66.67% | 0 | 3 | 6 (4) | |||||||
| May 20, 2013 11:05 |
čtvrtfinále | Rufin Guillaume (Fra.) [5] (104) | 54.43% | 2 | 6 | 6 | I H2H O AI | ||||
| Harrison Ryan (USA) [1 BYE] (85) | 45.57% | 0 | 3 | 4 | |||||||
| May 20, 2013 12:00 |
osmfinále | Jouan Romain (Fra.) (305) | 47.57% | 2 | 6 | 6 | I H2H O AI | ||||
| Kuznetsov Alex (USA) (173) | 52.43% | 0 | 4 | 3 | |||||||
| May 19, 2013 00:00 |
osmfinále | Harrison Ryan (USA) [1 BYE] (85) | 2 | 7 | 7 | I H2H O AI | |||||
| Polansky Peter (Kan.) (212) | 0 | 6 (4) | 5 | ||||||||
| May 19, 2013 00:00 |
osmfinále | Rufin Guillaume (Fra.) [5] (104) | 2 | 6 | 6 | I H2H O AI | |||||
| Massa Alexandre (Fra.) (1237) | 0 | 0 | 1 | ||||||||
| May 19, 2013 00:00 |
osmfinále | Silva Dutra Rogerio (Braz.) [2 BYE] (90) | 2 | 7 | 7 | I H2H O AI | |||||
| Giannessi Alessandro (Tal.) (264) | 0 | 6 (3) | 5 | ||||||||
| May 19, 2013 00:00 |
osmfinále | De Bakker Thiemo (Hol.) [3 BYE] (92) | 2 | 6 | 6 | I H2H O AI | |||||
| Olaso-De La Rica Guillermo (Špan.) (276) | 0 | 4 | 3 | ||||||||
| May 19, 2013 00:00 |
osmfinále | Stakhovsky Sergiy (Ukr.) [4 BYE] (102) | 2 | 6 | 6 | 7 | I H2H O AI | ||||
| Starace Potito (Tal.) (293) | 1 | 3 | 7 (2) | 6 (5) | |||||||
| May 19, 2013 16:20 |
osmfinále | Laaksonen Henri (Švaj.) (259) | 66.07% | 2 | 4 | 6 | 6 | I H2H O AI | |||
| Garin Christian (Chile) (520) | 33.93% | 1 | 6 | 1 | 1 | ||||||
| May 19, 2013 14:30 |
osmfinále | Cecchinato Marco (Tal.) (358) | 37.23% | 2 | 6 | 7 | 6 | I H2H O AI | |||
| Serra Florent (Fra.) [7] (130) | 62.77% | 1 | 7 (5) | 5 | 2 | ||||||
| May 19, 2013 13:15 |
1. kolo | Laaksonen Henri (Švaj.) (259) | 46.88% | 2 | 6 | 6 | I H2H O AI | ||||
| Mannarino Adrian (Fra.) [6] (109) | 53.12% | 0 | 3 | 2 | |||||||
| May 19, 2013 10:00 |
1. kolo | Massa Alexandre (Fra.) (1237) | 38.34% | 2 | 6 | 7 | I H2H O AI | ||||
| Olivetti Albano (Fra.) (310) | 61.66% | 0 | 3 | 5 | |||||||
| May 19, 2013 10:00 |
1. kolo | Rufin Guillaume (Fra.) [5] (104) | 63.77% | 2 | 6 | 6 | I H2H O AI | ||||
| Burquier Gregoire (Fra.) (292) | 36.23% | 0 | 3 | 1 | |||||||
| May 19, 2013 10:00 |
1. kolo | Giannessi Alessandro (Tal.) (264) | 52.00% | 2 | 3 | 6 | 6 | I H2H O AI | |||
| Samper-Montana Jordi (Špan.) (253) | 48.00% | 1 | 6 | 3 | 3 | ||||||
| May 19, 2013 12:00 |
1. kolo | Jouan Romain (Fra.) (305) | 52.66% | 2 | 7 | 1 | 6 | I H2H O AI | |||
| Mahut Nicolas (Fra.) (164) | 47.34% | 1 | 5 | 6 | 3 | ||||||
| May 19, 2013 13:00 |
1. kolo | Kuznetsov Alex (USA) (173) | 54.79% | 2 | 6 | 3 | 7 | I H2H O AI | |||
| Zopp Jurgen (Est.) [8] (155) | 45.21% | 1 | 3 | 6 | 6 (1) | ||||||
| May 19, 2013 12:40 |
1. kolo | Olaso-De La Rica Guillermo (Špan.) (276) | 53.11% | 2 | 6 | 7 | I H2H O AI | ||||
| Pierson Alexandre (Fra.) [WC] | 46.89% | 0 | 2 | 6 (3) | |||||||
| May 19, 2013 10:00 |
1. kolo | Cecchinato Marco (Tal.) (358) | 63.10% | 2 | 6 | 6 | I H2H O AI | ||||
| Fransen Stephan (Hol.) (1075) | 36.90% | 0 | 3 | 4 | |||||||
| May 19, 2013 10:00 |
1. kolo | Serra Florent (Fra.) [7] (130) | 61.43% | 2 | 6 | 6 | I H2H O AI | ||||
| Guez David (Fra.) (183) | 38.57% | 0 | 3 | 1 | |||||||
| May 19, 2013 12:00 |
1. kolo | Starace Potito (Tal.) (293) | 60.47% | 2 | 7 | 6 | I H2H O AI | ||||
| Mertinak Michal (Svk) (851) | 39.53% | 0 | 6 (0) | 3 | |||||||
| May 19, 2013 13:15 |
1. kolo | Garin Christian (Chile) (520) | 65.79% | 2 | 6 | 6 | I H2H O AI | ||||
| Commin Cedrick (Fra.) (1238) | 34.21% | 0 | 3 | 2 | |||||||
| May 19, 2013 11:45 |
1. kolo | Polansky Peter (Kan.) (212) | 36.22% | 2 | 7 | 6 | I H2H O AI | ||||
| Eysseric Jonathan (Fra.) (238) | 63.78% | 0 | 6 (1) | 3 | |||||||
