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ATP Bolton 2019 predictions
| ATP Bolton 2019 predictions / Veľká Británia, hala , ATP Bolton 2019 Tenis live dotace: 25 tis. USD |
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| Apr 7, 2019 11:40 |
finále | Van De Zandschulp Botic (Hol.) (497) | 52.11% | 2 | 7 | 6 | 7 | I H2H O AI | |||
| Sijsling Igor (Hol.) (424) | 47.89% | 1 | 6 (2) | 7 (6) | 5 | ||||||
| Apr 6, 2019 11:05 |
semifinále | Sijsling Igor (Hol.) (424) | 52.86% | 2 | 6 | 6 | I H2H O AI | ||||
| Glasspool Lloyd (V.Br.) (430) | 47.14% | 0 | 2 | 0 | |||||||
| Apr 6, 2019 12:30 |
semifinále | Van De Zandschulp Botic (Hol.) (497) | 55.91% | 2 | 6 | 6 | 7 | I H2H O AI | |||
| Lenz Julian (Nem.) (396) | 44.09% | 1 | 3 | 7 (9) | 5 | ||||||
| Apr 5, 2019 11:05 |
čtvrtfinále | Glasspool Lloyd (V.Br.) (430) | 64.62% | 1 | I H2H O AI | ||||||
| Huesler Marc-Andrea (Švaj.) (357) | 35.38% | 0 | |||||||||
| Apr 5, 2019 11:05 |
čtvrtfinále | Lenz Julian (Nem.) (396) | 45.74% | 2 | 6 | 6 | I H2H O AI | ||||
| Van Rijthoven Tim (Hol.) (439) | 54.26% | 0 | 3 | 3 | |||||||
| Apr 5, 2019 13:35 |
čtvrtfinále | Sijsling Igor (Hol.) (424) | 48.22% | 2 | 6 | 6 | I H2H O AI | ||||
| Hoyt Evan (V.Br.) (490) | 51.78% | 0 | 2 | 2 | |||||||
| Apr 5, 2019 11:05 |
čtvrtfinále | Van De Zandschulp Botic (Hol.) (497) | 60.14% | 2 | 6 | 6 | I H2H O AI | ||||
| Brouwer Gijs (Hol.) (415) | 39.86% | 0 | 4 | 1 | |||||||
| Apr 4, 2019 15:10 |
osmfinále | Van De Zandschulp Botic (Hol.) (497) | 54.19% | 2 | 7 | 6 | I H2H O AI | ||||
| Broady Liam (V.Br.) (335) | 45.81% | 0 | 5 | 2 | |||||||
| Apr 4, 2019 14:05 |
osmfinále | Sijsling Igor (Hol.) (424) | 56.17% | 2 | 6 | 6 | I H2H O AI | ||||
| Joncour Ronan (Fra.) (751) | 43.83% | 0 | 1 | 2 | |||||||
| Apr 4, 2019 11:10 |
osmfinále | Glasspool Lloyd (V.Br.) (430) | 56.00% | 2 | 6 | 6 | I H2H O AI | ||||
| McHugh Aidan (V.Br.) (499) | 44.00% | 0 | 3 | 2 | |||||||
| Apr 4, 2019 11:00 |
osmfinále | Lenz Julian (Nem.) (396) | 50.88% | 2 | 6 | 7 | I H2H O AI | ||||
| Nijboer Ryan (Hol.) (504) | 49.12% | 0 | 3 | 6 (6) | |||||||
| Apr 4, 2019 11:10 |
osmfinále | Brouwer Gijs (Hol.) (415) | 52.28% | 2 | 6 | 6 | I H2H O AI | ||||
| Findel-Hawkins Jack (V.Br.) (668) | 47.72% | 0 | 4 | 2 | |||||||
| Apr 4, 2019 11:10 |
osmfinále | Hoyt Evan (V.Br.) (490) | 52.61% | 2 | 7 | 7 | I H2H O AI | ||||
| Bergs Zizou (Bel.) (422) | 47.39% | 0 | 6 (1) | 6 (9) | |||||||
| Apr 4, 2019 12:25 |
osmfinále | Van Rijthoven Tim (Hol.) (439) | 51.95% | 2 | 6 | 6 | I H2H O AI | ||||
| Escoffier Antoine (Fra.) (381) | 48.05% | 0 | 2 | 4 | |||||||
| Apr 4, 2019 11:00 |
osmfinále | Huesler Marc-Andrea (Švaj.) (357) | 59.00% | 2 | 6 | 7 | I H2H O AI | ||||
| Johnson Luke (V.Br.) (692) | 41.00% | 0 | 4 | 6 (4) | |||||||
| Apr 3, 2019 11:10 |
1. kolo | McHugh Aidan (V.Br.) (499) | 41.48% | 2 | 6 | 6 | I H2H O AI | ||||
| Ejupovic Elmar (Nem.) (409) | 58.52% | 0 | 4 | 1 | |||||||
| Apr 3, 2019 11:00 |
1. kolo | Joncour Ronan (Fra.) (751) | 46.15% | 2 | 6 | 6 | I H2H O AI | ||||
| Pauffley Neil (V.Br.) (627) | 53.85% | 0 | 1 | 4 | |||||||
| Apr 3, 2019 15:20 |
1. kolo | Bergs Zizou (Bel.) (422) | 53.06% | 2 | 6 | 6 | I H2H O AI | ||||
| Grynkowski Piotr (Poľ.) (1632) | 46.94% | 0 | 4 | 2 | |||||||
| Apr 3, 2019 11:00 |
1. kolo | Nijboer Ryan (Hol.) (504) | 51.46% | 2 | 6 | 7 | 6 | I H2H O AI | |||
| Houghton George (V.Br.) (1164) | 48.54% | 1 | 7 (6) | 6 (10 | 0 | ||||||
| Apr 3, 2019 12:50 |
1. kolo | Findel-Hawkins Jack (V.Br.) (668) | 58.46% | 2 | 6 | 6 | I H2H O AI | ||||
| Gueydan Quentin (Fra.) (1653) | 41.54% | 0 | 2 | 4 | |||||||
| Apr 3, 2019 11:10 |
1. kolo | Broady Liam (V.Br.) (335) | 51.85% | 2 | 6 | 6 | I H2H O AI | ||||
| Binding Jonathan (V.Br.) (1046) | 48.15% | 0 | 3 | 2 | |||||||
| Apr 3, 2019 15:50 |
1. kolo | Escoffier Antoine (Fra.) (381) | 44.07% | 2 | 6 | 6 | I H2H O AI | ||||
| Guinard Manuel (Fra.) (457) | 55.93% | 0 | 4 | 4 | |||||||
| Apr 3, 2019 13:40 |
1. kolo | Van Rijthoven Tim (Hol.) (439) | 59.53% | 2 | 6 | 3 | 6 | I H2H O AI | |||
| Leshem Edan (Izr.) (450) | 40.47% | 1 | 3 | 6 | 4 | ||||||
| Apr 2, 2019 11:00 |
1. kolo | Brouwer Gijs (Hol.) (415) | 58.86% | 2 | 7 | 6 | 6 | I H2H O AI | |||
| Gray Jonathan (V.Br.) (651) | 41.14% | 1 | 6 (2) | 7 (6) | 4 | ||||||
| Apr 2, 2019 12:20 |
1. kolo | Lenz Julian (Nem.) (396) | 58.38% | 2 | 6 | 7 | I H2H O AI | ||||
| Griffith William (USA) (640) | 41.62% | 0 | 0 | 5 | |||||||
| Apr 2, 2019 11:10 |
1. kolo | Hoyt Evan (V.Br.) (490) | 52.07% | 2 | 6 | 6 | I H2H O AI | ||||
| Mertens Yannick (Bel.) (429) | 47.93% | 0 | 3 | 3 | |||||||
| Apr 2, 2019 14:30 |
1. kolo | Sijsling Igor (Hol.) (424) | 57.59% | 2 | 6 | 6 | I H2H O AI | ||||
| Durasovic Viktor (Nór.) (364) | 42.41% | 0 | 1 | 2 | |||||||
| Apr 2, 2019 11:10 |
1. kolo | Glasspool Lloyd (V.Br.) (430) | 47.57% | 2 | 3 | 7 | 6 | I H2H O AI | |||
| Redlicki Martin (USA) (389) | 52.43% | 1 | 6 | 5 | 3 | ||||||
| Apr 2, 2019 13:10 |
1. kolo | Johnson Luke (V.Br.) (692) | 41.31% | 2 | 5 | 6 | 6 | I H2H O AI | |||
| Matusevich Anton (V.Br.) (1532) | 58.69% | 1 | 7 | 2 | 3 | ||||||
| Apr 2, 2019 14:10 |
1. kolo | Huesler Marc-Andrea (Švaj.) (357) | 58.79% | 2 | 4 | 6 | 7 | I H2H O AI | |||
| Bothwell Peter (Ír.) (613) | 41.21% | 1 | 6 | 4 | 6 (8) | ||||||
| Apr 2, 2019 11:10 |
1. kolo | Van De Zandschulp Botic (Hol.) (497) | 56.40% | 2 | 6 | 6 | I H2H O AI | ||||
| Peniston Ryan (V.Br.) (682) | 43.60% | 0 | 1 | 3 | |||||||
