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ATP Hong Kong I 2019 predictions
| ATP Hong Kong I 2019 predictions / Hongkong, tvrdý , ATP Hong Kong I 2019 Tenis live dotace: 25 tis. USD |
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| Jun 15, 2019 06:30 |
finále | Ratiwatana Sanchai (Tha.) / Ratiwatana Sonchat (Tha.) |
58.70% | 2 | 6 | 4 | 10 | I H2H O | |||
| Gao Xin (1994) (Čína) / Yeung Pak Long (Hong.) |
41.30% | 1 | 3 | 6 | 8 | ||||||
| Jun 14, 2019 10:00 |
semifinále | Gao Xin (1994) (Čína) / Yeung Pak Long (Hong.) |
2 | 6 | 6 | I H2H O | |||||
| Duncan Scott (V.Br.) / Lazdins Arturs (Lot.) |
0 | 4 | 2 | ||||||||
| Jun 14, 2019 06:00 |
semifinále | Ratiwatana Sanchai (Tha.) / Ratiwatana Sonchat (Tha.) |
62.50% | 2 | 6 | 6 | I H2H O | ||||
| Wong Chun Hun (Hong.) / Zhu Michael (USA) |
37.50% | 0 | 4 | 4 | |||||||
| Jun 14, 2019 08:40 |
čtvrtfinále | Duncan Scott (V.Br.) / Lazdins Arturs (Lot.) |
45.78% | 2 | 7 | 7 | I H2H O | ||||
| Ichikawa Taisei (Jap.) / Mochizuki Yuki (Jap.) |
54.22% | 0 | 6 (5) | 6 (4) | |||||||
| Jun 13, 2019 14:00 |
čtvrtfinále | Gao Xin (1994) (Čína) / Yeung Pak Long (Hong.) |
57.69% | 2 | 6 | 6 | I H2H O | ||||
| Court Jayden (Aus.) / Crnokrak Alexander (Aus.) |
42.31% | 0 | 1 | 1 | |||||||
| Jun 13, 2019 14:30 |
čtvrtfinále | Wong Chun Hun (Hong.) / Zhu Michael (USA) |
54.22% | 2 | 6 | 6 | I H2H O | ||||
| Yue Ching Ho Sunny (Hong.) / Zhang Zheng Qi Jonathan (Hong.) |
45.78% | 0 | 2 | 1 | |||||||
| Jun 13, 2019 14:00 |
čtvrtfinále | Ratiwatana Sanchai (Tha.) / Ratiwatana Sonchat (Tha.) |
60.00% | 2 | 6 | 6 | I H2H O | ||||
| Tseng Chun Hsin (Taipei) / Wong Hong-kit (Hong.) |
40.00% | 0 | 1 | 2 | |||||||
| Jun 12, 2019 13:00 |
osmfinále | Duncan Scott (V.Br.) / Lazdins Arturs (Lot.) |
39.44% | 1 | 3 | I H2H O | |||||
| Matsui Toshihide (Jap.) / Uesugi Kaito (Jap.) |
60.56% | 0 | 6 | ||||||||
| Jun 12, 2019 12:30 |
osmfinále | Ichikawa Taisei (Jap.) / Mochizuki Yuki (Jap.) |
54.82% | 2 | 6 | 7 | I H2H O | ||||
| Lee Hsin-Han (Taipei) / Wong Coleman (Hong.) |
45.18% | 0 | 1 | 5 | |||||||
| Jun 12, 2019 13:05 |
osmfinále | Gao Xin (1994) (Čína) / Yeung Pak Long (Hong.) |
61.43% | 2 | 6 | 6 | I H2H O | ||||
| Ayap Sagadat (Kaz.) / Velotti Agustin (Arg.) |
38.57% | 0 | 4 | 2 | |||||||
| Jun 12, 2019 11:30 |
osmfinále | Court Jayden (Aus.) / Crnokrak Alexander (Aus.) |
44.59% | 2 | 7 | 6 | I H2H O | ||||
| Prasanth Vijay-Sundar (Ind.) / Vidal Azorin Jose Fco. (Špan.) |
55.41% | 0 | 5 | 3 | |||||||
| Jun 12, 2019 11:00 |
osmfinále | Yue Ching Ho Sunny (Hong.) / Zhang Zheng Qi Jonathan (Hong.) |
51.41% | 2 | 6 | 7 | I H2H O | ||||
| Tam Ching Yeung Michael (Hong.) / Wai Ching Wah (Hong.) |
48.59% | 0 | 2 | 5 | |||||||
| Jun 12, 2019 13:35 |
osmfinále | Wong Chun Hun (Hong.) / Zhu Michael (USA) |
55.21% | 2 | 6 | 6 | I H2H O | ||||
| Chan Pak Hong Issac (Hong.) / Yao Tsz Yan Adrian (Hong.) |
44.79% | 0 | 2 | 4 | |||||||
| Jun 12, 2019 11:35 |
osmfinále | Tseng Chun Hsin (Taipei) / Wong Hong-kit (Hong.) |
53.27% | 2 | 6 | 6 | I H2H O | ||||
| Kai Wai Yu (Hong.) / Zheng Yili (Čína) |
46.73% | 0 | 2 | 2 | |||||||
| Jun 12, 2019 11:30 |
osmfinále | Ratiwatana Sanchai (Tha.) / Ratiwatana Sonchat (Tha.) |
55.94% | 2 | 6 | 6 | I H2H O | ||||
| Glvac Andrej (Svk) / Mendoza Jurence Zosimo (Fili.) |
44.06% | 0 | 4 | 2 | |||||||
